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  • in reply to: Projects plugin – one more subargument to get file name #6884
    spectre
    Member

    Thank you for the clarification.

    I probably did not explain my point right. Let’s consider a following example.

    Assume we have a solution, say, D:xworksamplesmy_solution.eesln
    $(Solution) gives
    D:xworksamplesmy_solution.eesln
    as it should.

    I tried $(Solution,f) and it gave
    D:xworksamplesmy_solution

    But what I would like to have is just
    my_solution

    That is, just file name, no path.

    I mostly need this to construct the paths like the following:
    D:xworksamplesdebugmy_solution.smth
    ( $(Solution,d)debug$(Solution,).smth )

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